The School Lockers Puzzle

Posted on September 3, 2021 by Administrator Posted in Computer Science, Python - Advanced, Python Challenges, Solved Challenges

On the first day of school, the principal of Locker High school decides to conduct an experiment. The school has exactly 1,000 students and 1,000 lockers all lined up alongside the main corridor of the school.

The principal asks the first student to walk down the main corridor of the school to close all the lockers.
The principal then asks the second student to walk down the main corridor and open every other locker.
The principal then asks the third student to walk down the main corridor and either open every third locker if it is closed, or close it if it is open.
The fourth student will then repeat the same process for every fourth locker.
And so on, till the last of the 1,000 students repeats this process for every 1,000^th locker, so in fact, just opening the 1,000^th locker if it is closed, or closing it if it is already open.

At the end of this experiment the principal decides to count the number of lockers which are closed.

It is possible to solve this puzzle using your mathematical skills, however in this challenge, your task is to implement a computer program (using Python) to simulate this experiment and at the end, count and output the total number of lockers which are closed.

We have started the code and completed three sections of the code as follows:

Step 1:
We start by initialising an array/list of 1,000 values representing the 1,000 lockers:

0 will represent an open locker,
1 will represent a closed locker.

“To start with all the lockers a open!”

lockers = [0] * 1000

Step 2:

“The first student walks down the corridor to close all the lockers!”

for i in range(0,1000):
  lockers[i] = 1

A similar approach will need to be implemented to reproduce the actions of the remaining 999 students! This will be your task!

Step 3:

“At the end, the principal of the school counts how many lockers are closed!”

total = 0 
for i in range(0,1000):
   total = total + lockers[i]
   
print("Total number of lockers closed: " + str(total))

Python Code

You will need to complete the following code to solve this challenge:

The Principal’s padlock

The solution to the above challenge is the combination of the principal’s padlock. Use the output of your code to see if you can unlock this padlock!

Solution...

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2D Dice Grid Scoring Algorithm

Posted on August 24, 2021 by Administrator Posted in Computer Science, Python - Intermediate, Python Challenges, Solved Challenges

This challenge is based on a 4×4 grid of dice (16 dice in total). Each game starts by shaking the grid to generate a new grid of 16 values.

All dice are 6-sided dice, generating random values between 1 and 6 when the grid is shaken. The grid can be simplified by showing the actual dice values:

Once the new grid is set, its score can be calculated by identifying specific patterns as follows:

Start with a score of 0,
If all four corners are even numbers, add 20 pts to the score,
If all four corners are odd numbers, add 20 pts to the score,
If all four dice on a diagonal are even numbers, add 20 pts to the score,
If all four dice on a diagonal are odd numbers, add 20 pts to the score,
If all four dice on on any row are even numbers, add 20 pts to the score,
If all four dice on on any row are odd numbers, add 20 pts to the score,
If all four dice on on any column are even numbers, add 20 pts to the score,
If all four dice on on any column are odd numbers, add 20 pts to the score,
Add to the score the total value (sum) of all 16 dice.

So for example, with the above grid, we can calculate the score of the grid as follows:

Python Implementation

To help you with this challenge we have started the code for you by creating 4 functions to:

Generate/shake the grid of 16 dice.
Display the 4×4 grid on screen.
Check if a number is even.
Check if a number is odd.

We have also implemented the first section of the scoring algorithm, by initialising the grid score to 0 and by checking if all four corners are even. If so the score is increased by 20pts.

Your task is to complete the following code to implement the full scoring algorithm using the 10 rules mentioned above.

Solution...

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Tagged with: 2D Array

Diagonal Difference Calculator

Posted on August 18, 2021 by Administrator Posted in Computer Science, Python - Intermediate, Python Challenges, Solved Challenges

Let’s consider a square matrix of n x n. (n columns and n rows). The diagonal difference of a square matrix is the absolute difference between the sums of its diagonal.

Let’s look at an example based on the following 3 x 3 square matrix:

Here is how we would calculate the diagonal difference for this matrix:

Python Challenge

We have created a Python script that asks the user to input the dimension n of a square matrix (any positive integer value). Our python scripts generates a n x n matrix using random values and displays it on screen as a 2D grid.

Your task is to complete this script to automatically calculate the diagonal difference of the given matrix. (Make sure this value is always a positive value!)

Python Code

Extension Task #1

Your first extension task is to create an additional function to calculate the sum of the 4 corner values of the square matrix:

Extension Task #2

Your second extension task is create an additional function to calculate the average value of all values stored in the matrix.

Solution...

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Tagged with: 2D Array

Wind Speed Conversions and the Beaufort Scale

Posted on May 26, 2021 by Administrator Posted in Computer Science, Python - Intermediate, Python Challenges, Solved Challenges

Before going to sea, any sailor should check the marine weather forecast to check on different aspects of the weather including the direction and strength of the wind (wind speed).

The wind speed can be measured using different units such as mph (miles per hour), km/h (km per hour) but sailors tend to prefer to use knots. A knot represents a speed of 1 nautical mile per hour, and a nautical mile is exactly 1,852 meters!

The Beaufort wind force scale was introduced in 1805 by a Royal Navy officer, Francis Beaufort. It relates wind speeds to observed conditions at sea or on land. Nowadays, the scale contains thirteen values (from zero to twelve): A force 0 wind represents very calm wind conditions whereas a force 12 wind represents a Hurricane-force wind!

Here is the full Beaufort scale:

Beaufort Wind Force Scale
Force	Description	Wind speed	Wave height	Sea conditions	Land conditions
0	Calm	< 1 knot	0 ft (0 m)	Sea like a mirror	Smoke rises vertically.
1	Light air	1–3 knots	0–1 ft	Ripples with appearance of scales are formed, without foam crests	Direction shown by smoke drift but not by wind vanes.
2	Light breeze	4–6 knots	1–2 ft	Small wavelets still short but more pronounced; crests have a glassy appearance but do not break	Wind felt on face; leaves rustle; wind vane moved by wind.
3	Gentle breeze	7–10 knots	2–4 ft	Large wavelets; crests begin to break; foam of glassy appearance; perhaps scattered white horses	Leaves and small twigs in constant motion; light flags extended.
4	Moderate breeze	11–16 knots	3.5–6 ft	Small waves becoming longer; fairly frequent white horses	Raises dust and loose paper; small branches moved.
5	Fresh breeze	17–21 knots	6–10 ft	Moderate waves taking a more pronounced long form; many white horses are formed; chance of some spray	Small trees in leaf begin to sway; crested wavelets form on inland waters.
6	Strong breeze	22–27 knots	9–13 ft	Large waves begin to form; the white foam crests are more extensive everywhere; probably some spray	Large branches in motion; whistling heard in telegraph wires; umbrellas used with difficulty.
7	High wind, moderate gale, near gale	28–33 knots	13–19 ft	Sea heaps up and white foam from breaking waves begins to be blown in streaks along the direction of the wind; spindrift begins to be seen	Whole trees in motion; inconvenience felt when walking against the wind.
8	Gale, fresh gale	34–40 knots	18–25 ft	Moderately high waves of greater length; edges of crests break into spindrift; foam is blown in well-marked streaks along the direction of the wind	Twigs break off trees; generally impedes progress.
9	Strong/severe gale	41–47 knots	23–32 ft	High waves; dense streaks of foam along the direction of the wind; sea begins to roll; spray affects visibility	Slight structural damage (chimney pots and slates removed).
10	Storm, whole gale	48–55 knots	29–41 ft	Very high waves with long overhanging crests; resulting foam in great patches is blown in dense white streaks along the direction of the wind; on the whole the surface of the sea takes on a white appearance; rolling of the sea becomes heavy; visibility affected	Seldom experienced inland; trees uprooted; considerable structural damage.
11	Violent storm	56–63 knots	37–52 ft	Exceptionally high waves; small- and medium-sized ships might be for a long time lost to view behind the waves; sea is covered with long white patches of foam; everywhere the edges of the wave crests are blown into foam; visibility affected	Very rarely experienced; accompanied by widespread damage.
12	Hurricane force	≥ 64 knots	≥ 46 ft	The air is filled with foam and spray; sea is completely white with driving spray; visibility very seriously affected	Devastation.

Python Challenge

In this challenge we will write a python script that:

lets the user enter a wind speed in the unit of their choice (mph, km/h, knot)
converts this wind speed in knots and lookup the matching find force,
looks up for the matching wind force from the Beaufort scale,
outputs the wind force and both the matching sea and land conditions

Python Code

You can complete the python code using the following trinket:

Solution...

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Tagged with: Dictionary

Circle Geometry Functions

Posted on May 6, 2021 by Administrator Posted in Computer Science, Python - Intermediate, Python Challenges

In this challenge we will create a library of functions to apply the different formulas based on the geometry of circles.

For each function, you will need to design the algorithm using either Pseudo-code or a flowchart, implement the function using the Python trinket provided below and use another algorithm to test your function.

CircumferenceAreaArcSector: PerimeterSector: AreaChordSegment: PerimeterSegment: Area

Write a function called getCircumference() that takes one parameter/argument: the radius of a circle.

Your function should calculate and return the circumference (perimeter) of this circle..