Number 2520?

Posted on November 11, 2019 by Administrator Posted in Computer Science, Python - Intermediate, Python Challenges

Did you know that 2520 is the smallest number exactly divisible by all integers from 1 to 10.

The aim of this challenge is to write a python script to work out this number from its definition.

Note that a number (a) is exactly divisible (whole division) by another number (b) if the remainder of divising a per b is equal to 0.

In pseudo code:

a = INPUT("Type a whole number (integer)")
a = INPUT("Type another whole number (integer)")
IF (a MOD b) == 0 THEN
   OUTPUT(a + " is exactly divisible by " + b)
ELSE
  OUTPUT(a + " is not exactly divisible by " + b)
END IF

a = INPUT("Type a whole number (integer)")

a = INPUT("Type another whole number (integer)")

IF (a MOD b) == 0 THEN

OUTPUT(a + " is exactly divisible by " + b)

ELSE

OUTPUT(a + " is not exactly divisible by " + b)

END IF

In Python the MOD operator (remainder) is %.

a = int(input("Type a whole number (integer)"))
b = int(input("Type another whole number (integer)"))
if (a % b) == 0:
   print(str(a) + " is exactly divisible by " + str(b))
else:
  print(str(a) + " is not exactly divisible by " + str(b))

a = int(input("Type a whole number (integer)"))

b = int(input("Type another whole number (integer)"))

if (a % b) == 0:

print(str(a) + " is exactly divisible by " + str(b))

else:

print(str(a) + " is not exactly divisible by " + str(b))

We are going to use this operator in our code to find out the smallest number exactly divisible by all integers from 1 to 10.

Note that we know, per definition, that this number will have to be greater or equal to 10. So, using an iterative approach (in this case, a while loop) we will test every number from 10, one at a time up until we find a number that is divisible by all the numbers from 1 to 10.